Lisp is an old language. Very old. Today there are many Lisps and no single language is called Lisp today. Actually, there are as many Lisps as Lisp programmers. That’s because you become a Lisp programmer when you go alone in the desert and write an interpreter for your flavor of lisp with a stick on the sand.
There are two main Lisps these days: Common Lisp and Scheme, both standards with many implementations. The various Common Lisps are more or less the same, the various Schemes are the same at the basic level but then they differ, sometimes quite significantly. They are both interesting but I personally failed to make a practical use of any of those. Both bother me in different ways, and of all the other Lisps, my favorite is Clojure. I’m not going to dig into that, it’s a personal matter and it’ll take me a long time.
Clojure, like any other Lisp, has a REPL (Read Eval Print Loop) where we can write code and get it to run immediately. For example:
5 ;=> 5 "Hello world" ;=> "Hello world"
We can call a function like this:
(println "Hello World") ; Hello World ;=> nil
It printed “Hello World” and returned
nil. I know the parenthesis look misplaced but there’s a reason for that and you’ll notice it’s not that different from Javaish snippet:
except that Clojure uses the parenthesis in that way for all operations:
(+ 1 2) ;=> 3
In Clojure we also have vectors:
[1 2 3 4] ;=> [1 2 3 4]
'symbol ;=> symbol
The reason for the quote is that symbols are treated as variables. Without the quote, Clojure would try to find its value. Same for lists:
'(li st) ;=> (li st)
and nested lists
'(l (i s) t) ;=> (l (i s) t)
Here’s how defining a variable and using it looks like
(def hello-world "Hello world") ;=> #'user/hello-world hello-world ;=> "Hello world"
I’m going very fast, skipping lots of details and maybe some things are not totally correct. Bear with me, I want to get to the good stuff.
In Clojure you create functions like this:
(fn [n] (* n 2)) ;=> #<user$eval1$fn__2 user$eval1$fn__2@175bc6c8>
That ugly long thing is how a compiled function is printed out. Don’t worry, it’s not something you see often. That’s a function, as created by the operator
fn, of one argument, called
n, that multiplies the argument by two and returns the result. In Clojure as in all Lisps, the value of the last expression of a function is returned.
If you look at how a function is called:
(println "Hello World")
you’ll notice the pattern is, open parens, function, arguments, close parens. Or saying it in another way, a list where the first item is the operator and the rest are the arguments.
Let’s call that function:
((fn [n] (* n 2)) 10) ;=> 20
What I’m doing there is defining an anonymous function and applying it immediately. Let’s give that function a name:
(def twice (fn [n] (* n 2))) ;=> #'user/twice
and then we can apply it by name:
(twice 32) ;=> 64
As you can see, functions are stored in variables like any other piece of data. Since that’s something that’s done very often, there’s a shortcut:
(defn twice [n] (* 2 n)) ;=> #'user/twice (twice 32) ;=> 64
Let’s make the function have a maximum of 100 by using an if:
(defn twice [n] (if (> n 50) 100 (* n 2))))
The if operator has three arguments, the predicate, the expresion to evaluate when the predicate is true and the one when it’s false. Maybe like this it’s easier to read:
(defn twice [n] (if (> n 50) 100 (* n 2)))
Enough basic stuff, let’s move to the fun stuff.
Let’s say you want to write Lisp backwards. The operator at the last position, like this:
(4 5 +)
Let’s call this language Psil (that’s Lisp backwards… I’m so smart). Obviously if you just try to run that it won’t work:
(4 5 +) ;=> java.lang.ClassCastException: java.lang.Integer cannot be cast to clojure.lang.IFn (NO_SOURCE_FILE:0)
That’s Clojure telling you that
4 is not a function (an object implementing the interface
It’s easy enough to write a function that converts from Psil to Lisp:
(defn psil [exp] (reverse exp))
The problem is that when I try to use it, like this:
(psil (4 5 +)) ;=> java.lang.ClassCastException: java.lang.Integer cannot be cast to clojure.lang.IFn (NO_SOURCE_FILE:0)
I obviously get an error, because before psil is called, Clojure tries to evaluate the argument, that is,
(4 5 +) and that fails. We can call it explicitly turning the argument into a list, like this:
(psil '(4 5 +)) ;=> (+ 5 4)
but that didn’t evaluate it, it just reversed it. Evaluating it is not that hard though:
(eval (psil '(4 5 +))) ;=> 9
You can start to see the power of Lisp. The fact that the code is just a bunch of nested lists allows you to easily generate running programs out of pieces of data.
If you don’t see it, just try doing it in your favorite language. Start with an array containing two numbers and a plus and end up with the result of adding them. You probably end up concatenating strings or doing other nasty stuff.
This way of programming is so common on Lisp that it was abstracted away in a reusable thing call macros. Macros are functions that receive the unevaluated arguments and the result is then evaluated as Lisp.
Let’s turn psil into a macro:
(defmacro psil [exp] (reverse exp))
The only difference is that I’m now calling
defmacro instead of
defn. This is quite remarkable:
(psil (4 5 +)) ;=> 9
Note how the argument is not valid Clojure yet I didn’t get any error. That’s because it’s not evaluated until psil processes it. The
psil macro is getting the argument as data. When you hear people say that in Lisp code is data, this is what they are talking about. It’s data you can manipulate to generate other programs. This is what allows you to invent your own programming language on top of Lisp and have any semantics you need.
There’s an operator on Clojure called
macroexpand which makes a macro skip the evaluation part so you can see what’s the code that’s going to be evaluated:
(macroexpand '(psil (4 5 +))) ;=> (+ 5 4)
You can think of a macro as a function that runs at compile time. The truth is, in Lisp, compile time and run time are all mixed and you are constantly switching between the two. We can make our psil macro very verbose to see what’s going on, but before, I have to show you
do is a very simple operator, it takes a list of expressions and runs them one after the other but they are all grouped into one single expression that you can pass around, for example:
(do (println "Hello") (println "world")) ; Hello ; world ;=> nil
With do, we can make the macro return more than one expression and to make it verbose:
(defmacro psil [exp] (println "compile time") `(do (println "run time") ~(reverse exp)))
That new macro prints “compile time” and returns a
do that prints
“run time” and runs exp backwards. The back-tick,
` is like the quote
' except that allows you to unquote inside it by using the tilde,
~. Don’t worry if you don’t understand that yet, let’s just run it:
(psil (4 5 +)) ; compile time ; run time ;=> 9
As expected, compile time happens before runtime. If we use
macroexpand things will get more clear:
(macroexpand '(psil (4 5 +))) ; compile time ;=> (do (clojure.core/println "run time") (+ 5 4))
You can see that the compile phase already happened and we got an expression that will print “run time” and then evaluate
(+ 5 4). It also expanded
println into its full form,
clojure.core/println, but you can ignore that. When that code is evaluated at run time.
The result of the macro is essentially:
(do (println "run time") (+ 5 4))
and in the macro it was written like this:
`(do (println "run time") ~(reverse exp))
The back-tick essentially created a kind of template where the tilde marked parts for evaluating (
(reverse exp)) while the rest was left at is.
There are even more surprises behind macros, but for now, it’s enough hocus pocus.
The power of this technique may not be totally apparent yet. Following my Why I love Smalltalk post, let’s imagine that Clojure didn’t come with an
cond. It’s not the best example in this case, but it’s simple enough.
cond is like a
case in other languages:
(cond (= x 0) "It's zero" (= x 1) "It's one" :else "It's something else")
cond we can create a function
my-if straightforward enough:
(defn my-if [predicate if-true if-false] (cond predicate if-true :else if-false))
and at first it seems to work:
(my-if (= 0 0) "equals" "not-equals") ;=> "equals" (my-if (= 0 1) "equals" "not-equals") ;=> "not-equals"
but there’s a problem. Can you spot it?
my-if is evaluating all its arguments, so if we do something like this, the result is not as expected:
(my-if (= 0 0) (println "equals") (println "not-equals")) ; equals ; not-equals ;=> nil
my-if into a macro:
(defmacro my-if [predicate if-true if-false] `(cond ~predicate ~if-true :else ~if-false))
solves the problem:
(my-if (= 0 0) (println "equals") (println "not-equals")) ; equals ;=> nil
This is just a glimpse into the power of macros. One very interesting case was when object oriented programming was invented (Lisp is older than that) and Lisp programmers wanted to use it.
C programmers had to invent new languages, C++ and Objective C, with their compilers. Lisp programmers created a bunch of macros, like defclass, defmethod, etc. All thanks to macros. Revolutions, in Lisp, tend to just be evolutions.
Thanks to Gonzalo Fernández, Alessandro Di Maria, Vladimir Filipović for reading drafts of this.